10x^2+1x=9.975

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Solution for 10x^2+1x=9.975 equation:



10x^2+1x=9.975
We move all terms to the left:
10x^2+1x-(9.975)=0
We add all the numbers together, and all the variables
10x^2+x-9.975=0
a = 10; b = 1; c = -9.975;
Δ = b2-4ac
Δ = 12-4·10·(-9.975)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-20}{2*10}=\frac{-21}{20} =-1+1/20 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+20}{2*10}=\frac{19}{20} =19/20 $

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